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Question

A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same effort, he throws the ball vertically upwards. The maximum height attained by the ball is :

A
100 m
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B
80 m
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C
60 m
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D
50 m
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Solution

The correct option is D 50 m

We know that horizontal range is maximum if the angle of projection is 45o and is given by

Rmax = u2 / g

Here, Rmax = 100 m

so, u2 / g = 100 m

If the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the ground

Hmax = u2 / 2g = 100 /2 = 50 m.


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