A cricketer has a certain average for 9 innings, In the tenth inning he scores 100 runs there by increasing his average by 8 runs. His new average is

28

runs

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24

runs

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32

runs

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20

runs

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Solution

The correct option is A $28$ runs
$= \frac{9 x + 100}{10} = x + 8$
$=\Rightarrow 9 x + 100 = 10 x + 80$
$= x = 20$
New average, $= ¯ x = 20 + 8 = 28$

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A cricketer has a certain average for 9 innings, In the tenth inning he scores 100 runs there by increasing his average by 8 runs. His new average is

The correct option is A 28 runs=9x+10010=x+8=⇒9x+100=10x+80=x=20New average, =¯x=20+8=28

The correct option is A $28$ runs
$= \frac{9 x + 100}{10} = x + 8$
$=\Rightarrow 9 x + 100 = 10 x + 80$
$= x = 20$
New average, $= ¯ x = 20 + 8 = 28$