A cricketer hits a sixer.The cricket ball moves up with a velocityof $2 m s^{- 1}$ and falls down. Its initial velocity while falling down willbe

1 m s^{- 1}

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1 m s^{- 2}

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0 m s^{- 1}

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2 m s^{- 1}

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Solution

The correct option is C $0 m s^{- 1}$
The body will start falling down once it reaches its maximum height and its velocity in upward direction becomes zero. So, the moment it starts falling down, its initial velocity will be zero

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