A cricketer's scores in five ODI matches are as follows: 10, 34, 45, 50, 26. The mean of the following data would be

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Solution

The correct option is B 33
Mean $= \frac{S u m o f a l l o b s e r v a t i o n s}{N u m b e r o f o b s e r v a t i o n s}$

Mean $= \frac{10 + 34 + 45 + 50 + 26}{5}$
Mean $= \frac{165}{5} = 33$

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