Question

A cricketer whose bowling average is 12.4 runs per wicket, takes 5 wicket for 26 runs and thereby decreases his average by 0.4. The number of wickets taken by him till the last match was :

• A. $64$
• B. $72$
• C. $80$
• D. $85$

Answer 1

Answer: (D)

$85$

Let the number of wickets taken by bowler after the match be N.

So, number of runs given by bowler after match $=(N-5)\times 12.4$ $+26$

$=12.4N-62+26$

$=12.4N-36$

Average of bowler after match $=\frac{12.4N-36}{N}$

As per question , average of bowler after match $=12.4-0.4=12$

Equating both averages , we get

$\frac{12.4N-36}{N}$ $=12$

$12.4N-12N=36$

$N=\frac{36}{0.4}$

$N=90$

So, Number of wickets taken by bowler till last match $=N-5=90-5=85$