A crop of wheat uses up to 20 kg of nitrogen per hectare of soil. What is the mass of the fertilizer calcium nitrate required to replace the nitrogen in a 10-hectare field?
$(C a = 40, N = 1, O = 16)$

1171.4 kg

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1182 kg

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1181 kg

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2171 kg

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Solution

The correct option is A
1171.4 kg

Total nitrogen required by $10$ hectares = $10 \times 20$
$= 200 k g$
$164$ parts of $C a (N O_{3})_{2}$ gives 28 gm of $N_{2}$
$200$ parts of $N_{2} = \frac{164 \times 200}{28}$
$= 1171.4 k g$

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A crop of wheat uses up to 20 kg of nitrogen per hectare of soil. What is the mass of the fertilizer calcium nitrate required to replace the nitrogen in a 10-hectare field?(Ca=40, N=1, O=16)

The correct option is A 1171.4 kgTotal nitrogen required by 10 hectares = 10×20 =200kg164 parts of Ca(NO3)2 gives 28 gm of N2200 parts of N2=164×20028=1171.4kg

A crop of wheat uses up to 20 kg of nitrogen per hectare of soil. What is the mass of the fertilizer calcium nitrate required to replace the nitrogen in a 10-hectare field?
$(C a = 40, N = 1, O = 16)$

The correct option is A
1171.4 kg

Total nitrogen required by $10$ hectares = $10 \times 20$
$= 200 k g$
$164$ parts of $C a (N O_{3})_{2}$ gives 28 gm of $N_{2}$
$200$ parts of $N_{2} = \frac{164 \times 200}{28}$
$= 1171.4 k g$