A cross is made between breeding lines of pea plants with axillary and terminal flowers. If 1240 $F_{2}$ progeny are obtained, how many of them produce terminal flowers?

1240

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310

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620

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Zero

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Solution

The correct option is B
310

This is a simple monohybrid cross. Terminal flowers is the dominant and axial flowers is a recessive trait. Out of 1240 F₂ progeny, plants producing axial flowers and terminal flowers will be obtained in 3:1 ratio. Hence plants with terminal flowers $= 1240 \times \frac{1}{4} = 310$

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A cross is made between breeding lines of pea plants with axillary and terminal flowers. If 1240 $F_{2}$ progeny are obtained, how many of them produce terminal flowers?

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A cross is made between breeding lines of pea plants with axillary and terminal flowers. If 1240 F2 progeny are obtained, how many of them produce terminal flowers?

The correct option is B 310 This is a simple monohybrid cross. Terminal flowers is the dominant and axial flowers is a recessive trait. Out of 1240 F2 progeny, plants producing axial flowers and terminal flowers will be obtained in 3:1 ratio. Hence plants with terminal flowers =1240×14=310

A cross is made between breeding lines of pea plants with axillary and terminal flowers. If 1240 $F_{2}$ progeny are obtained, how many of them produce terminal flowers?