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Question

A cross is made between true breeding lines of pea plants with axillary (A) and terminal (a) flowers. What is the ratio between the number of possible genotypes of homozygous and heterozygous plants in F2 progeny?


A

3:1

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B

1:2:1

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C

1:1

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D

1:1:2

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Solution

The correct option is C

1:1


Genotype of parent plant with axillary flower: AA
Genotype of parent plant with terminal flower: aa

F1 : AA X aa
F1 generation produces only heterozygous (Aa) offsprings.

F2 : Aa X Aa
Out of possible F2 progenies in monohybrid cross:

  • 14th are homozygous dominant (AA).
  • 12 are heterozygous dominant(Aa).
  • 14th are homozygous recessive (aa).

Thus, the fraction of homozygous progeny is 14 + 14 = 12, while the fraction of heterozygous being 12 .
Therefore, the ratio between all the homozygous and heterozygous plants is:
12 : 12 = 1:1


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