In the above cross, how many plants are homozygous with axillary flowers and heterozygous with axillary flowers in the $F_{2}$ generation?

310 & 620

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620 & 620

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310 & 310

No worries! We‘ve got your back. Try BYJU‘S free classes today!

620 & 310

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is A
310 & 620

The $F_{2}$ genotypic ratio of Mendel’s monohybrid cross is 1:2:1. Out of the $F_{2}$ progeny 1/4th are homozygous plants with axillary flowers. Homozygous plants with axillary flowers $= 1240 \times \frac{1}{4} = 310$ . Heterozygous plants with axillary flowers $= 1240 \times \frac{1}{2} = 620$ . Thus option A is correct.

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In the above cross, how many plants are homozygous with axillary flowers and heterozygous with axillary flowers in the F2 generation?

In the above cross, how many plants are homozygous with axillary flowers and heterozygous with axillary flowers in the $F_{2}$ generation?