A cross is made between true breeding lines of pea plants with axillary and terminal flowers. If 1240 progeny are obtained, how many plants are homozygous with axillary flowers and heterozygous with axillary flowers in the F2 generation?
310 & 620
The F2 genotypic ratio of Mendel’s monohybrid cross is 1:2:1. Out of the F2 progeny 1/4th are homozygous plants with axillary flowers. Homozygous plants with axillary flowers =1240×14=310 . Heterozygous plants with axillary flowers =1240×12=620. Thus option A is correct.