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Dihybrid Cross

A cross was m...

Question

A cross was made between a pure round yellow seeded pea plant with wrinkled green seeded pea plant.

The $F_{1}$ progeny obtained is heterozygous round yellow seeded pea plants that were selfed and total 400 seeds are collected. What is the total number of seeds with recombinant traits?

A

200

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B

150

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C

100

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D

75

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Solution

The correct option is B 150
A cross was made between a pure round yellow seeded pea plant (RRYY) with wrinkled green seeded pea plant (rryy). The yellow colour is dominant over green and round seed shape is dominant over wrinkled seed shape.
In F2 generation mendel obtain 16 zygotes or 16 plants.

Phenotypic ratio :

Round yellow Round green Wrinkled yellow Wrinkled green

9/16 3/16 3/16 1/16

Now, out of total 16 individuals 6 are recombinant type so in 400 seeds 150 seeds will be recombinant type.

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Q. Mendel first crossed pure-bred pea plants having round -yellow seeds with pure-bred pea plants having wrinkled -green seeds and found that only round- yellow seeds were produced in the

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generation pea plants having round-yellow seeds were cross-bred by self-pollination, then peas having round-yellow seeds, round green seeds, wrinkled-yellow seeds and wrinkled -green seeds were produced. Mendel collected a total of 2160 seeds.

(a) What will be the number of
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(ii) wrinkled green seeds
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(b) Which 'ratio' as established by Mendel have you made use of in answering the part (a) above?

Q. Heterozygous round and yellow seeded pea plants were selfed and total 800 seeds are collected. What is the total number of seeds with first dominant and second recessive traits?

Q. Heterozygous round and yellow seeded pea plants were selfed and total 800 seeds are collected . what is the total number of seeds with first dominant and second reccessive traits?

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