A crystal formed by two elements $X$ and $Y$ in cubic structure. $X$ atoms are at the corners of cube while $Y$ atoms are at the face center. The formula of he compound will be:

X Y

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X Y_{2}

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X_{2} Y_{3}

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X Y_{3}

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Solution

The correct option is D $X Y_{3}$
Since, X atoms are present at corners of cube.
So, number of X atoms = $\frac{1}{8} \times 8 = 1$
Y atoms are present at face centres.
So, number of Y atoms = $\frac{1}{2} \times 6 = 3$ .
So, the formula of compound is ${X Y}_{3}$ .
So, option D is correct.

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A crystal formed by two elements X and Y in cubic structure. X atoms are at the corners of cube while Y atoms are at the face center. The formula of he compound will be:

The correct option is D XY3Since, X atoms are present at corners of cube.So, number of X atoms = 18×8=1Y atoms are present at face centres.So, number of Y atoms = 12×6=3.So, the formula of compound is XY3.So, option D is correct.

A crystal formed by two elements $X$ and $Y$ in cubic structure. $X$ atoms are at the corners of cube while $Y$ atoms are at the face center. The formula of he compound will be:

The correct option is D $X Y_{3}$
Since, X atoms are present at corners of cube.
So, number of X atoms = $\frac{1}{8} \times 8 = 1$
Y atoms are present at face centres.
So, number of Y atoms = $\frac{1}{2} \times 6 = 3$ .
So, the formula of compound is ${X Y}_{3}$ .
So, option D is correct.