A crystal has linear coefficient of expansion 9 - 10-5 - 12 - 10-5- 7 - 10-5 -K along three mutually perpendicular directions the volume expansion coefficient is

The correct option is D 28 × 10^ 5 / k In crystal system, ϵ_v = ϵ_x + ϵ_y + ϵ_z ⇒ϵ_v = 9 × 10^ 5 + 12 × 10^ 5 + 7 × 10^ 5 = 28 × 10^ 5 /K ...

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Standard XII

Chemistry

Crystal Lattice and Unit Cell

A crystal has...

Question

A crystal has linear coefficient of expansion $9 \times 10^{- 5}, 12 \times 10^{- 5}, 7 \times 10^{- 5} / K$ along three mutually perpendicular directions the volume expansion coefficient is

27 \times 10^{- 5} / k

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26 \times 10^{- 5} / k

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21 \times 10^{- 5} / k

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28 \times 10^{- 5} / k

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Solution

The correct option is D $28 \times 10^{- 5} / k$
In crystal system,
$ϵ_{v} = ϵ_{x} + ϵ_{y} + ϵ_{z}$
$\Rightarrow ϵ_{v} = 9 \times 10^{- 5} + 12 \times 10^{- 5} + 7 \times 10^{- 5} = 28 \times 10^{- 5} / K$

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A crystal has linear coefficient of expansion 9×10−5,12×10−5,7×10−5/K along three mutually perpendicular directions the volume expansion coefficient is

The correct option is D 28×10−5/kIn crystal system,ϵv=ϵx+ϵy+ϵz⇒ϵv=9×10−5+12×10−5+7×10−5=28×10−5 /K

A crystal has linear coefficient of expansion $9 \times 10^{- 5}, 12 \times 10^{- 5}, 7 \times 10^{- 5} / K$ along three mutually perpendicular directions the volume expansion coefficient is

The correct option is D $28 \times 10^{- 5} / k$
In crystal system,
$ϵ_{v} = ϵ_{x} + ϵ_{y} + ϵ_{z}$
$\Rightarrow ϵ_{v} = 9 \times 10^{- 5} + 12 \times 10^{- 5} + 7 \times 10^{- 5} = 28 \times 10^{- 5} / K$