wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A crystal is made up of particles A and B. A forms FCC packing and B occupies all the octahedral voids. If all the particles along one of the diagonal plane in the unit cell are removed, then, the formula of the crystal would be :

(a) AB (b) A5B7 (c) A7B5 (d) none of these

Open in App
Solution

A forms FCC lattice. So the number of atoms =4
B atoms are in octahedral voids. Number of octahedral voids = Number of atoms = 4
We are removing voids from diagonal of body (diagonal plane). But octahedral voids are in body centre and at edge centre. Tetrahedral voids only will be present in diagonal. So removing voids from diagonal means removing tetrahedral voids. Octahedral voids will not be affected.
So the formula of the compound is A4B4 or AB

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon