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Question

A crystal of lead (II) sulphide has NaCl structure. In this crystal the shortest distance between a Pb2+ ion and S2
ion is 300 pm. What is the volume of a unit cell of lead sulphide ?

A
216×1024cm3
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B
2.7×1023cm3
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C
216×1030cm3
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D
27×1030cm3
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Solution

The correct option is A 216×1024cm3
Side length of unit cell of crystal = 2×300=600 pm

vol = (side length)3=(600)3pm3=216×106×1030cm3=216×1024cm3

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