A crystal of lead (II) sulphide has NaCl structure. In this crystal the shortest distance between a Pb2+ ion and S2− ion is 300 pm. What is the volume of a unit cell of lead sulphide ?
A
216×10−24cm3
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B
2.7×10−23cm3
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C
216×10−30cm3
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D
27×10−30cm3
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Solution
The correct option is A216×10−24cm3 Side length of unit cell of crystal = 2×300=600pm