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Azeotropic Mixtures

A crystalline...

Question

A crystalline solid $X$ reacts with $d i l . H C l$ to liberate a gas $Y$ . $Y$ decolourises acidified $K M n O_{4}$ . When a gas $Z$ is slowly passed into an aqueous solution of $Y$ , colloidal sulfur is obtained. $X$ and $Z$ could be, respectively:

{N a}_{2} S O_{4}, H_{2} S

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{N a}_{2} S O_{4}, S O_{2}

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{N a}_{2} S, S O_{3}

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{N a}_{2} S O_{3}, H_{2} S

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Solution

The correct option is D ${N a}_{2} S O_{3}, H_{2} S$
X and Z could be ${N a}_{2} S O_{3}, H_{2} S$ respectively.

${N a}_{2} S O_{3}$ (crystalline solid) reacts with dil.HCl to liberate $S O_{2}$ .
${N a}_{2} S O_{3} + 2 H C l (d i l) \to 2 N a C l + S O_{2} ↑ + H_{2} O$
$S O_{2}$ decolourises acidified $K M n O_{4}$ .
$5 S O_{2} + 2 K M n O_{4} + 2 H_{2} O \to K_{2} S O_{4} + 2 M n S O_{4} + 2 H_{2} S O_{4}$
When $H_{2} S$ gas is slowly passed into an aqueous solution of $S O_{2}$ , colloidal sulphur is obtained.
$S O_{2} + 2 H_{2} S \to 2 H_{2} O + 3 S ↓$

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