A crystallizes in HCP close packing and B occupied $\frac{1}{2}$ of octahedral voids.

Calculate the formula of the compound?

What if 2 ions of A are removed from the corner of each unit cell?

What is the new crystal formula?

$A_{2} B, A_{17} B_{9}$ respectively

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$A B_{2}, A_{17} B$ respectively

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$A_{3} B, A B_{9}$ respectively

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$A_{4} B, A_{17} B_{9}$ respectively

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Solution

The correct option is A
$A_{2} B, A_{17} B_{9}$ respectively

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Similar questions

A crystallizes in HCP close packing and B occupied $\frac{1}{2}$ of octahedral voids.

Calculate the formula of the compound?

What if 2 ions of A are removed from the corner of each unit cell?

What is the new crystal formula?

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Q. A crystal is made up of particles A, B, and C, A forms fcc packing, B occupies all octahedral voids and C occupies all tetrahedral voids. If all the particles along one body diagonal are removed, then the formula of the crystal would be:

Q. Ferric oxide crystallizes in an hcp of

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.
If true enter 1, else enter 0.

A crystal is made up of particles A and B. A forms FCC packing and B occupies all the octahedral voids. If all the particles along one of the diagonal plane in the unit cell are removed, then, the formula of the crystal would be :

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A crystallizes in HCP close packing and B occupied 12 of octahedral voids. Calculate the formula of the compound? What if 2 ions of A are removed from the corner of each unit cell? What is the new crystal formula?

The correct option is A A2B,A17B9 respectively

A crystallizes in HCP close packing and B occupied $\frac{1}{2}$ of octahedral voids.

Calculate the formula of the compound?

What if 2 ions of A are removed from the corner of each unit cell?

What is the new crystal formula?

The correct option is A
$A_{2} B, A_{17} B_{9}$ respectively