A crystallizes in HCP close packing and B occupied $\frac{1}{2}$ of octahedral voids.

Calculate the formula of the compound?

What if 2 ions of A are removed from the corner of each unit cell?

What is the new crystal formula?

$A_{2} B, A_{17} B_{9}$ respectively

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$A B_{2}, A_{17} B$ respectively

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$A_{3} B, A B_{9}$ respectively

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$A_{4} B, A_{17} B_{9}$ respectively

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Solution

The correct option is A
$A_{2} B, A_{17} B_{9}$ respectively

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A crystallizes in HCP close packing and B occupied 12 of octahedral voids. Calculate the formula of the compound? What if 2 ions of A are removed from the corner of each unit cell? What is the new crystal formula?

The correct option is A A2B,A17B9 respectively

A crystallizes in HCP close packing and B occupied $\frac{1}{2}$ of octahedral voids.

Calculate the formula of the compound?

What if 2 ions of A are removed from the corner of each unit cell?

What is the new crystal formula?

The correct option is A
$A_{2} B, A_{17} B_{9}$ respectively