$A + {C S}_{2} + H g {C l}_{2}$ gives $C_{2} H_{5} - N = C = S$ . Thus compound $A$ is:

C_{2} H_{5} {N H}_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{2} H_{5} N H C_{2} H_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C H}_{3} - C H = N O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C H}_{3} {C H}_{2} {N O}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C_{2} H_{5} {N H}_{2}$
The compound A is ethyl amine. It reacts with carbon disulphide in presence of mercury (II) chloride to form ethyl isothiocyanate.
This reaction is Hofmann mustard oil reaction and is given by primary amines only. Thus it is test for primary amines. Isothiocyanates have pungent smell similar to mustard oil.

Suggest Corrections

Similar questions

O H^{⊖}

C H_{3} - C H | C_{2} H_{5} - B r

C H_{3} - B r | C | C_{2} H_{5} - C H_{3}

C H_{3} - C H | C_{2} H_{5} - C H_{2} B r

C_{2} H_{5} {N H}_{2} + {C S}_{2} + H g {C l}_{2} h e a t - - \to . . . . + H g S + H C l

{C H}_{3} - C_{2} H_{5} | C H - {C H}_{2} - {C_{2} H_{5} | C H - C H}_{3}

{C H}_{3} - C H = C H - C_{2} H_{5} - - \to H C l

C_{2} H_{5} O C_{2} H_{5}

C H_{3} - O - C | H C H_{3} - C H_{3}

Join BYJU'S Learning Program