Question

A cube (density $0.5gm/cc$) of side $10cm$ is floating in water kept in a cylindrical beaker of base area $1500c{m}^2$.
When a mass $m$ is kept on wooden block the level of water rises in the beaker by $2mm$. Find the mass $m$.

Answer 1

$=mg+0.5\times \left(10\times 10\times 10\right)\times g=1\times \left(5.2\times 10\times 10\right)\times g$

$=m=5.2\times 10\times 10-5\times 10\times 10$

$=520-500$

$m=20g$

We get$,$

$m=20g$