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Question

A cube (density 0.5 gm/cc of side 10 cm is floating in water kept in a cylindrical beaker of base area 1500 cm2. When a mass m is kept on wooden block the level of water rises in the beaker by 2 mm. The mass m is

A
400 gm
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B
300 gm
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C
200 gm
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D
100 gm
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Solution

The correct option is B 300 gm
Draw a diagram of given problem.

Calculate volume of water displaced by block.
Given,
Base area of the block, A=1500 cm2

Height, h=2 mm=0.2 cm

Let the cube dips further by y cm and water level rises by 2 mm.

Volume of water displaced,

=[1500(10×10)]×210

=280 cm3

Calculate mass m to rise water by 2 mm.
Volume of extra depth of wood,

100×y=100y

Equating the volumes,

100y=280 y=2.8 cm

Therefore, extra upthrust

pwater×(2.8+0.2)×100g=mg

m=300 gm

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