Question

A cube enclose a charge of $1C$. What is the electric flux through the surface of the cube?

Answer 1

According to gauss's law

Electric flux through the closed surface is$\frac{1}{e}$ times the charge enclosed by it.

Where,

$e$ is electrical permittivity

Here,

Electric flux$=\frac{q}{6e}$

$\Rightarrow \frac{1}{6\times 8.85\times {10}^{-12}}$

$=1.475\times {10}^{-}12N{m}^2{C}^{-}1$