Question

A cube has a side of length $1.2\times {10}^{-2}m$. Its volume upto correct significant figures is:

• A. $1.7\times {10}^{-6}{m}^3$
• B. $1.73\times {10}^{-6}{m}^3$
• C. $1.70\times {10}^{-6}{m}^3$
• D. $1.732\times {10}^{-6}{m}^3$

Answer 1

The correct option is A $1.7\times {10}^{-6}{m}^3$

Here,
Length of the cube, $L=1.2\times {10}^{–2}m$
Volume of the cube, $V=(1.2\times {10}^{-2}m{)}^3$
$=1.728\times {10}^{-6}{m}^3$
As the result can have only two significant figures, therefore, on rounding off, we get
$V=1.7\times {10}^{-6}{m}^3$