a cube has a surface area of 42 square metres. what is the surface area of the one face?

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Solution

$Let the length of each side of the cube = s Now, TSA of cube = 42 {cm}^{2} \Rightarrow 6 s^{2} = 42 \Rightarrow s^{2} = 7 Hence, surface area of one face of cube = s^{2} = 7 {cm}^{2}$

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a cube has a surface area of 42 square metres. what is the surface area of the one face?

Let the length of each side of the cube = sNow, TSA of cube = 42 cm2⇒6s2 = 42⇒s2 = 7Hence, surface area of one face of cube = s2 = 7 cm2

$Let the length of each side of the cube = s Now, TSA of cube = 42 {cm}^{2} \Rightarrow 6 s^{2} = 42 \Rightarrow s^{2} = 7 Hence, surface area of one face of cube = s^{2} = 7 {cm}^{2}$