A cube has an edge measuring $9 c m$ . Find the number of cubes of edge $3 c m$ that can be cut off from it.

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Solution

$\begin{matrix} \Rightarrow V o l u m e o f c u b e e d g e 9 c m = 9^{3} c m^{3} \Rightarrow a n d v o l u m e o f c u b e e d g e 3 c m = 3^{3} c m^{3} T h e n, n u m b e r o f c u b e s t h a t c a n b e c u t = \frac{9^{3}}{3^{3}} = \frac{27}{1} = 27 \end{matrix}$

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