wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cube is inscribed inside the sphere of diameter 10 cm, it is given that corners of the cube touches the surface of the sphere then, what's the total surface area of the cube?

A
1200 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
400 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
600 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 200 cm2
Let the length of the side of the cube be a cm.

We know that,
total surface area of cube
=6(side length)2

Given that,
corners of the cube touches the surface of the sphere.
diameter of sphere
= length of body diagonal of cube

Now,
applying pythagoras theorem in cube along the body diagonal
a2+(2a)2=102
[(side)2+(side diagonal)2=(body diagonal)2]
3a2=100
a2=1003

Hence, total surface area of the cube
= 6a2
=6×1003
= 200 cm2

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Surface Area of Solids
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon