Question

A cube of $9cm$ edge is immersed completely in a rectangular vessel containing water. If the dimension of the base are $15cm$ and $12cm$, find the rise in water level in the vessel.

Answer 1

Volume of cube$=9\times 9\times 9{cm}^3=729{cm}^3$

area of vessel$=15$cm$\times 12$cm$=180{cm}^2$

height$=\frac{729{cm}^3}{180{cm}^2}=4.05$cm