Question

A cube of ice whose side is 4.0 cm is allowed to melt. The volume of water found to be 58.24 ${cm}^3$. Find the density of ice.

Answer 1

mass 1 cm cubic of water $=1g$

therefore mass of $58.24g$ of water$=58.24\times 1$

$=58.24$

volume of ice cube $=4^3$

$=12cm$ cubed

therefore density of ice $=\frac{mass}{volume}$

$=\frac{58.24}{12}$

$=0.91gcm-3$