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Question


A cube of side 1 m whose base is rigidly fixed to the surface in contact is given a charge Q=2 C at its top surface. [Charge is uniformly distributed on top surface only].
Electric field of 50 N/C also exist as shown in figure. Elastic energy stored in cube if modulus of rigidity is 3×1010 N/m2 is x×108 J. Find x upto two decimal points

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Solution

Energy=12×stress×strain×volume
η=stressstrain
Energy=12(stress)2η×(volume)
Stress=FA=QEa2
Energy=12(QEa2)2×a3η=12 Q2E2ηa
=22×5022×3×1010×1=16.67×108 J

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