A cube of side 1m fixed at the lower face is acted upon by a tangential force F on its upper surface. If shearing strain is 10−2 due to force F, find the distance that the upper face is sheared with respect to lower face.
A
10−3 m
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B
10−2 m
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C
10−4 m
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D
10−1 m
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Solution
The correct option is B10−2 m
The figure represents the plane, which is showing the shearing action along one of the face of cube. F is the shearing force acting along the face of cube. AA′=CC′=x is the distance by which face is sheared. ⇒Shearing strain(ϕ)=AA′AB Or, ϕ=xL ⇒10−2=xL L=1m given ∴x=L×10−2=10−2m