A cube of side 10 cm completely immersed in water experiences a buoyant force of 1000 N. Take $g = 10 m / s^{2}$ .

True

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False

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Solution

The correct option is B False
Archimedes' principle states that the buoyant force acting on
the immersed part of an object is equal to the weight of the fluid displaced by it.
The volume of the cube of side 10 cm is $1000 c m^{3} = 0.001 m^{3}$ , which is also equal to the volume of water displaced.
Mass of water displaced = Density x Volume $= 1000 k g / m^{3} \times 0.001 m^{3} = 1 k g (D e n s i t y o f w a t e r i s 1000 k g / m^{3})$
$W e i g h t o f w a t e r d i s p l a c e d = m g = 1 \times 10 N$
Hence, the water experiences a buoyant force of 10 N.

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A cube of side 10 cm completely immersed in water experiences a buoyant force of 1000 N. Take g=10m/s2.

A cube of side 10 cm completely immersed in water experiences a buoyant force of 1000 N. Take $g = 10 m / s^{2}$ .