A cube of side 2 m is placed in front of a concave mirror focal length 1m with its face P at a distance of 3 m and face Q at a distance of 5 m from the mirror. The distance between the images of face P and Q and height of images of P and Q are
For surface P,1v1=1f−1u=1−13=23⇒v1=32m
For surface Q,1v2=1f−1u=1−15=45⇒v2=54m
∴ v1−v2 = 0.25 cm
Magnification of P=v1u=3/23=12
∴ Height of P=12×2=1m
Magnification of Q=v2u=545=14
∴ Height of Q=14×2=0.5m