A cube of side $20 c m$ is floating on a liquid with $5 c m$ of the cube outside the liquid. If the density of liquid is $0.8 g m / c . c$ then the mass of the cube is

4.2 kg

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4.8 kg

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5 kg

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5.2 kg

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Solution

The correct option is C 4.8 kg
$Mass of cube = mass of liq. displace$

$d \times (20)^{3} = 0.8 \times 20 \times 20 \times 15$
$d = \frac{0.8 \times 5}{20}$
$d = 0.6$
$Mass = 0.6 \times (20)^{3} g m$
$= 0.6 \times 8 k g$
$= 4.8 k g$
$Answer : - (B)$

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A cube of side 20 cm is floating on a liquid with 5 cm of the cube outside the liquid. If the density of liquid is 0.8 gm/c.c then the mass of the cube is

The correct option is C 4.8 kg Mass of cube = mass of liq. displace d×(20)3=0.8×20×20×15d=0.8×520d=0.6 Mass =0.6×(20)3gm=0.6×8 kg=4.8 kg Answer :−(B)

A cube of side $20 c m$ is floating on a liquid with $5 c m$ of the cube outside the liquid. If the density of liquid is $0.8 g m / c . c$ then the mass of the cube is

The correct option is C 4.8 kg
$Mass of cube = mass of liq. displace$

$d \times (20)^{3} = 0.8 \times 20 \times 20 \times 15$
$d = \frac{0.8 \times 5}{20}$
$d = 0.6$
$Mass = 0.6 \times (20)^{3} g m$
$= 0.6 \times 8 k g$
$= 4.8 k g$
$Answer : - (B)$