A cube of side $20 c m$ is floating on a liquid with $5 c m$ of the cube outside the liquid. If the density of liquid is $0.8 g m / c c$ then the mass of the cube is

4.2 k g

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4.8 k g

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5 k g

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5.2 k g

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Solution

The correct option is B $4.8 k g$
Volume submerged $= 15 \times 20 \times 20 c m^{3}$
$15.0 \times 20 \times 20 \times 0.8 \times 10 = 20 \times 20 \times 20 \times ρ_{c} \times 10 \frac{12}{20} = ρ_{c}$
mass $= \frac{12}{20} \times 20 \times 20 \times 20 = 4800 g r a m = 4.8 k g$

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A cube of side 20cm is floating on a liquid with 5cm of the cube outside the liquid. If the density of liquid is 0.8gm/cc then the mass of the cube is

The correct option is B 4.8kgVolume submerged=15×20×20cm315.0×20×20×0.8×10=20×20×20×ρc×101220=ρcmass=1220×20×20×20=4800gram=4.8kg

A cube of side $20 c m$ is floating on a liquid with $5 c m$ of the cube outside the liquid. If the density of liquid is $0.8 g m / c c$ then the mass of the cube is

The correct option is B $4.8 k g$
Volume submerged $= 15 \times 20 \times 20 c m^{3}$
$15.0 \times 20 \times 20 \times 0.8 \times 10 = 20 \times 20 \times 20 \times ρ_{c} \times 10 \frac{12}{20} = ρ_{c}$
mass $= \frac{12}{20} \times 20 \times 20 \times 20 = 4800 g r a m = 4.8 k g$