A cube of side 3 units is formed using a set of smaller cubes of side 1 unit. Find the proportion of the number of faces of the smaller cubes visible to those which are not visible?

1:4

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1:3

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1:2

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2:3

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Solution

The correct option is C 1:2
Number of faces per cube = 6
Total number of cubes = 27
Total number of faces = 6 x 27 = 162
Number of visible faces = 54
Number of non-visible faces = 162 – 54 = 108
Their ratio = 54/108 = 1:2

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