A 4 cm cube is cut into 1 cm cubes. Calculate the total surface area of all the small cubes.

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Solution

Side of original cube = 4 cm

No. of 1 cm cubes $= \frac{4 \times 4 \times 4}{1 \times 1 \times 1} = 64$

$Now surface area of one cube = 6 \times (1)^{2}$

$= 6 \times 1 = 6 c m^{2}$

$and surface area of 64 cubes = 6 \times 64 c m^{2}$ $= 384 c m^{2}$

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A 4 cm cube is cut into 1 cm cubes. Calculate the total surface area of all the small cubes.

Side of original cube = 4 cm No. of 1 cm cubes =4×4×41×1×1=64 Now surface area of one cube = 6×(1)2 =6×1=6 cm2 and surface area of 64 cubes = 6×64 cm2=384 cm2

Side of original cube = 4 cm

No. of 1 cm cubes $= \frac{4 \times 4 \times 4}{1 \times 1 \times 1} = 64$

$Now surface area of one cube = 6 \times (1)^{2}$

$= 6 \times 1 = 6 c m^{2}$

$and surface area of 64 cubes = 6 \times 64 c m^{2}$ $= 384 c m^{2}$