A cube of side 4 cm is cut into cubes of side 1 cm. The ratio of the surface area of the original cube to that of cut out cube is

4:1

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8:1

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16:1

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64:1

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Solution

The correct option is C
16:1

Given, the ratio of the edge length of the original cube to cut out cube = 4:1
Surface area of cube = $6 {(s i d e)}^{2}$
$Required ratio = \frac{S u r f a c e a r e a o f o r i g i n a l c u b e}{S u r f a c e a r e a o f n e w c u b e} = \frac{6 \times 4^{2}}{6 \times 1^{2}} = \frac{16}{1}$
$∴$ Required ratio = 16:1

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A cube of side 4 cm is cut into cubes of side 1 cm. The ratio of the surface area of the original cube to that of cut out cube is

The correct option is C 16:1 Given, the ratio of the edge length of the original cube to cut out cube = 4:1 Surface area of cube = 6(side)2 Required ratio=Surface area of original cubeSurface area of new cube =6×426×12 =161 ∴ Required ratio = 16:1