Question

A cube of side $a$ is placed on an inclined plane of inclination $\theta$. What is the maximum value of $\theta$ so that the cube does not topple?

• A. ${15}^o$
• B. ${30}^o$
• C. ${45}^o$
• D. ${60}^o$

Answer 1

Answer: (C)

${45}^o$

The cube will not topple until the line of action of CM passes through the cube. Here COM is taken point O
That is,
$tan\theta =\frac{AX}{OX}=\frac{a/2}{a/2}$ or $\theta ={45}^o$