Question

A cubic casting of 50 mm side undergoes volumetric solidification shrinkage and volumetric solid contraction of 4% and 6% respectively. No riser is used. Assume uniform cooling in all directions. The side of the cube after solidification and contraction is

• A. $\text{48.32 mm}$
• B. $\text{49.96 mm}$
• C. $\text{49.94 mm}$
• D. $\text{49.90 mm}$

Answer 1

The correct option is A $\text{48.32 mm}$

$\text{Side of cube after solidification}$

$=\sqrt[3]{30.96\times {\left(50\right)}^3}=49.32mm$

$\text{Side of cube after contraction}$

$=\sqrt[3]{30.94\times {\left(49.32\right)}^3}=48.32mm$