A cubic meter of copper weighing $9000 k g$ is rolled into a square bar $9 m$ long. An exact cube is cut off from the bar. How much does it weight?

333.3 k g

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320.5 k g

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349.1 k g

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312.9 k g

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Solution

The correct option is A $333.3 k g$
Let side of square be a volume equal to $1$ .
Then, $a^{2} \times 9 = 1$
$⟹ a = \frac{1}{3}$ .
Volume of cube $= a^{3} = \frac{1}{27} m^{3}$ .
Therefore, Required weight $= 9000 \times \frac{1}{27} = 333.33 k g$ .
Hence, option $A$ is correct.

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A cubic meter of copper weighing 9000kg is rolled into a square bar 9m long. An exact cube is cut off from the bar. How much does it weight?

The correct option is A 333.3kgLet side of square be a volume equal to 1.Then, a2×9=1⟹a=13.Volume of cube =a3=127m3.Therefore, Required weight =9000×127=333.33kg.Hence, option A is correct.

A cubic meter of copper weighing $9000 k g$ is rolled into a square bar $9 m$ long. An exact cube is cut off from the bar. How much does it weight?

The correct option is A $333.3 k g$
Let side of square be a volume equal to $1$ .
Then, $a^{2} \times 9 = 1$
$⟹ a = \frac{1}{3}$ .
Volume of cube $= a^{3} = \frac{1}{27} m^{3}$ .
Therefore, Required weight $= 9000 \times \frac{1}{27} = 333.33 k g$ .
Hence, option $A$ is correct.