CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cubic polynomial P(x) is such that P(1)=1, P(2)=2, P(3)=3 and P(4)=5. The value of P(6) is:

A
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
13
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
16
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 16
Given P(1)=1,P(2)=2,P(3)=3,P(4)=5

Let f(x)=(P(x)x)

f(1)=P(1)1=11=0

f(2)=P(2)2=22=0

f(3)=P(3)3=33=0

f(x)=0,x=1,2,3

f(x)=a(x1)(x2)(x3)

P(x)=a(x1)(x2)(x3)+x

Put x=4

5=a(3)(2)(1)+4

a=16
P(x)=16(x1)(x2)(x3)+x
P(6)=16(5)(4)(3)+6=16

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Continuity of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon