Question

A cubic solid made up of two elements $P$ and $Q$. $P$ are at corners, $Q$ are at edge centers and Body Centers. Predict formula of the compound.

Answer 1

$P$ is present at corners of cube, so effective number of atoms of $P=\frac{1}{8}\times 8=1$

$Q$ is present at edge centers and body center. So, effective number of atoms of $Q=\frac{1}{4}\times 12+1=3+1=4$

So, $P:Q=1:4$

So, formula of compound is $P{Q}_4$