A cubical block having square cross section of side 2 m and of mass M=10 kg is resting over a platform moving at constant acceleration a=1m/s2. Coefficient of friction between the block and the platform is μ=0.1. A force F acts at the top of the cube as shown in Fig. Now match Column I with Column II.
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Solution
The force required to topple the block about O, Fa=Mag+Ma2×1 F=M+M2=55N and fmax=μmg=0.1×10×10=10N Force between 0-10N will do neither sliding or slipping. Force between 10-55 N will cause slipping. Force above 55 N will topple the block.