The correct option is
D 15 rad/sLet us suppose angular speed of the block after it hits
O is
ω about axis passing through
O.
From the diagram shown below:
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/987817/original_1.png)
When the block collides with the ridge, the impulsive force which operates will pass through point
O.
Therefore, net torque will be zero about
O.
On applying law of conservation of angular momentum.
Li=Lf ⇒mvl2=IOω where
l is the side of the cube.
[MOI of cubical block about point
O just as it hits it an starts to rotate is given by parallel axis theorem
IO=ml26+m(l√2)2]
⇒5×20×12=⎡⎣5×126+5×(1√2)2⎤⎦ω ⇒50=103ω ⇒ω=15 rad/s The angular speed of block after it hits
O is
15 rad/s.
Hence, option (d) is the correct answer.