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Question

A cubical block of mass M and edge a slides down a rough inclined plane of inclination θ with a uniform velocity. The torque of the normal force on the block about its centre has a magnitude

A
zero
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B
Mga
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C
Mgasinθ
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D
Mgasinθ2
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Solution

The correct option is D Mgasinθ2
Because the cubical block slides with a uniform velocity and does not topple, hence
Torque produced by weight = Torque due to normal force on the block
Torque due to normal force
= Torque due to weight
= Component of weight parallel to plane × distance from lower face
=(Mgsinθ)a2
Hence, the correct answer is option (d).


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