A cubical block of side $10 c m$ floats at the interface of an oil and water as shown in the figure. The density of oil is $0.6 g c m^{- 3}$ and the lower face of ice cube is $2 c m$ below the interface. The pressure above that of the atmosphere at the lower face of the block is

200 P a

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620 P a

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900 P a

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800 P a

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Solution

The correct option is C $800 P a$
$Δ P = ρ_{o i l} g h_{o i l} + ρ_{w} g h_{w}$
$= (600) (10) (10 \times 10^{- 2}) + (100) (1) (2 \times 10^{- 2})$
$= 800 P a$

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A cubical block of side 10cm floats at the interface of an oil and water as shown in the figure. The density of oil is 0.6gcm−3 and the lower face of ice cube is 2cm below the interface. The pressure above that of the atmosphere at the lower face of the block is

The correct option is C 800PaΔP=ρoilghoil+ρwghw =(600)(10)(10×10−2)+(100)(1)(2×10−2) =800Pa

A cubical block of side $10 c m$ floats at the interface of an oil and water as shown in the figure. The density of oil is $0.6 g c m^{- 3}$ and the lower face of ice cube is $2 c m$ below the interface. The pressure above that of the atmosphere at the lower face of the block is

The correct option is C $800 P a$
$Δ P = ρ_{o i l} g h_{o i l} + ρ_{w} g h_{w}$
$= (600) (10) (10 \times 10^{- 2}) + (100) (1) (2 \times 10^{- 2})$
$= 800 P a$