A cubical box with a lid has a length 30 cm. Find the cost of painting the outside and inside of the box at Rs. 2 per m. sq.

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Solution

Length of each side = 30cm
Cost of painting = Rs 2/ $m^{2}$
Area of one side = Area outside + Area inside
= 900 + 900 = 1800 $c m^{2}$
$= \frac{18 / 0 / 0}{100 \times 1 / 0 / 0} m^{2} = 0.18 m^{2}$
Total faces = 5
$∴ T o t a l a r e a = 0.18 \times 5 = 0.90 m^{2}$
$C o s t = 0.90 \times 2 = R s . 1.80$

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