A cubical vessel filled with a liquid of density $p$ is kept at rest on an inclined plane. What is the pressure difference between $A$ and $B$ ?

p g b

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p g (h_{1} - h_{2})

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p g l \frac{h_{2} - h_{1}}{b}

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p g b \frac{h_{2} - h_{1}}{l}

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Solution

The correct option is B $p g (h_{1} - h_{2})$
At A, $P_{A} = ρ g h_{1}$
At B, $P_{B} = ρ g h_{2}$
difference $= P_{A} - P_{B} = ρ g h_{1} - ρ g h_{2} = ρ g (h_{1} - h_{2})$
Hence option 'B' is correct.

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