A cubical vessel has a side with 'I' cm lenth contained a gas at a pressure of 'p'. when the side of the vessel is made $\frac{1}{2}$ cm, the pressure of gas becomes?

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$\frac{P}{8}$

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Solution

The correct option is D
8P

$P_{1}$ $V_{1}$ = $P_{2}$ $V_{2}$

P. $l^{3}$ = $p_{2}$ ${(\frac{1}{2})}^{3}$

$P_{2}$ = 8P

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