wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A cubical vessel of height 1m is full of water. What is the amount of work done in pumping water out of the vessel?
(Take g=10m/s2)

A
1250 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5000 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1000 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2500 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 5000 J
Step 1: Calculate potential energy of water
COM of water will lie at the center of vessel.
Assuming potential energy as 0 at bottom of the vessel.

Potential energy =mgh
(PE)initial=mgh2 ....(1)

and (PE)finaal=0 ...(2)

Step 2: Apply energy conservation
From energy conservation, we can say

Work=(ΔPE)

Work=[(PE)final(PE)initial]

From equation (1) and (2)

Work=(0mgh2)=mgh2

Volume of vessel =lbh=1m×1m×1m=1m3 and m=ρV

Work=ρVgh2=(1000Kg/m3)(1m3)(10m/s2)(1m)2 ρ=1000Kg/m3

Work=5000 Joule
Hence option B is correct.

2115351_467382_ans_9ba423e484124caf9b559e6304909906.png

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Power
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon